Yugabrat Gogoi
Last Activity: 10 Years ago
Please find your answer below
let the table be-
22 04 20 14 -1st row
now we have to make 4 rows and 4 columns.
now, and the first and the last number ie-22+14=36
now think any 2 number whose sum is 36
let the numbers be 11 and 25.
place it this way-
1st 2nd 3rd 4th
22 04 20 14 -1st row
-2nd row
-3rd row
11 25 -4th row
like the same way take the midle 2 numbers of the birth date ie-04 and 20.
add them. the result = 24 now think of any 2 number whose sum is 24 . let the nos be 09 and 15
now place them in the table like this at the ends.-
1st 2nd 3rd 4th
22 04 20 14 -1st row
-2nd row
-3rd row
09 11 25 15 -4th row
now add the numbers at the right corner ie 14 and 15. you will get 29.
again imagine any 2 numbers. let them be 19 and 10.
place them at the middle of left corner this way.-
1st 2nd 3rd 4th
22 04 20 14 -1st row
19 -2nd row
10 -3rd row
09 11 25 15 -4th row
now, add the numbers at the ends of left corner ie 22 and 9 .
you will get 31. let the different numbers whose sum is 31 be 27 and 4.
now place it at the middle of right corner this way-
1st 2nd 3rd 4th
22 04 20 14 -1st row
19 27 -2nd row
10 04 –3rd row
09 11 25 15 -4th row
now at the nubers at the end of 2nd of the right side ie 20 and 25. the sum is 45. let the other numbers whose sum is 45 be 44 and 01.
place in the middle of 2nd from left corner in this way-
1st 2nd 3rd 4th
22 04 20 14 -1st row
19 01 27 -2nd row
10 44 04 -3rd row
09 11 25 15 -4th row
now add the nubers at the end of 2nd from left side. ie-4 and 11.
do the sum and you will get 15. now add all the numbers of one row of the birth date and you will get 60.
now, substract the sum of the second row by 60. ie-60-(19+01+27)
you will get-13. place that at the remaining space of 2nd row.
do the same with the third row. ie 60-(10+44+4)
and you will get 2.
place it in this way-
1st 2nd 3rd 4th
22 04 20 14 -1st row
19 01 13 27 -2nd row
10 44 02 04 –3rd row
09 11 25 15 -4th row
and your magic square is finished. you will get all the sum equal to 60.
(note- try that there are no repeated number in the magic square)
(note- it will be only virtically and horizontally possible. Digonally the sum will be different)
hope you like this- regards Yugabrat Gogoi
